Java DOM4J解析器 - 修改XML文档

演示示例

这是我们需要修改的XML文档：

<?xml version="1.0"?>
<class>
   <student rollno="393">
      <firstname>dinkar</firstname>
      <lastname>kad</lastname>
      <nickname>dinkar</nickname>
      <marks>85</marks>
   </student>
   <student rollno="493">
      <firstname>Vaneet</firstname>
      <lastname>Gupta</lastname>
      <nickname>vinni</nickname>
      <marks>95</marks>
   </student>
   <student rollno="593">
      <firstname>jasvir</firstname>
      <lastname>singn</lastname>
      <nickname>jazz</nickname>
      <marks>90</marks>
   </student>
</class>

%uA0

演示示例：

DOM4jModifyXMLDemo.java

package com.yiibai.xml

import java.io.File
import java.io.IOException
import java.io.UnsupportedEncodingException
import java.util.Iterator
import java.util.List

import org.dom4j.Document
import org.dom4j.DocumentException
import org.dom4j.Element
import org.dom4j.Node
import org.dom4j.io.OutputFormat
import org.dom4j.io.SAXReader
import org.dom4j.io.XMLWriter

public class DOM4jModifyXMLDemo {
   public static void main(String[] args) {
      try {
         File inputFile = new File("input.txt")
         SAXReader reader = new SAXReader()
         Document document = reader.read( inputFile )

         Element classElement = document.getRootElement()

         List<Node> nodes = document.selectNodes("/class/student[@rollno=&apos493&apos]" )		       
         for (Node node : nodes) {
            Element element = (Element)node
            Iterator<Element> iterator=element.elementIterator("marks")
            while(iterator.hasNext()){
               Element marksElement=(Element)iterator.next()
               marksElement.setText("80")
            }
         }

         // Pretty print the document to System.out
         OutputFormat format = OutputFormat.createPrettyPrint()
         XMLWriter writer
         writer = new XMLWriter( System.out, format )
         writer.write( document )
      } catch (DocumentException e) {
         e.printStackTrace()
      } catch (UnsupportedEncodingException e) {         
         e.printStackTrace()
      } catch (IOException e) {
         e.printStackTrace()
      }
   }	
}

这将产生以下结果:

<?xml version="1.0" encoding="UTF-8"?>
<class> 
  <student rollno="393"> 
    <firstname>dinkar</firstname>  
    <lastname>kad</lastname>  
    <nickname>dinkar</nickname>  
    <marks>85</marks> 
  </student>  
  <student rollno="493"> 
    <firstname>Vaneet</firstname>  
    <lastname>Gupta</lastname>  
    <nickname>vinni</nickname>  
    <marks>80</marks> 
  </student>  
  <student rollno="593"> 
    <firstname>jasvir</firstname>  
    <lastname>singn</lastname>  
    <nickname>jazz</nickname>  
    <marks>90</marks> 
  </student> 
</class>

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