java.lang.String.hashCode()%uA0方法返回该字符串的哈希码。对于String对象的哈希码的计算方法为：
s[0]*31^(n-1) + s[1]*31^(n-2) + ... + s[n-1]%uA0其中，s[i]为字符串的第i个字符，n是字符串的长度，^表示求幂
声明
以下是java.lang.String.hashCode()方法的声明
public int hashCode()
参数
-
NA
返回值
此方法返回该对象的哈希码值。
异常
-
NA
例子
下面的例子显示java.lang.String.hashCode()方法的使用。
package com.yiibai import java.lang.* public class StringDemo { public static void main(String[] args) { Integer i = new Integer(50) Long l = new Long(50) Float f = new Float(50) Integer i2 = new Integer(0) // hash codes of different objects with same value are always same System.out.println("Hash code of " + i + " is = " + i.hashCode()) System.out.println("Hash code of " + l + " is = " + l.hashCode()) // hash code for float value i.e different from Integer and Long System.out.println("Hash code of " + f + " is = " + f.hashCode()) // hash code value of number zero(0) is zero(0) System.out.println("Hash code of " + i2 + " is = " + i2.hashCode()) String str = "this is yiibai" // hash code of string str System.out.println("Hash code of string is = " + str.hashCode()) } }
让我们编译并运行上述程序，这将产生以下结果：
Hash code of 50 is = 50 Hash code of 50 is = 50 Hash code of 50.0 is = 1112014848 Hash code of 0 is = 0 Hash code of string is = 643938959