%uA0java.lang.ThreadGroup.getMaxPriority()%uA0方法返回该线程组的最大优先级。线程是该组的一部分不可以比最高的优先级有较高的优先级。
声明
以下是java.lang.ThreadGroup.getMaxPriority()方法的声明
public final int getMaxPriority()
参数
-
NA
返回值
此方法返回该线程组线程的最高优先级。
异常
-
NA
例子
下面的例子显示java.lang.ThreadGroup.getMaxPriority()方法的使用。
package com.yiibai import java.lang.* public class ThreadGroupDemo implements Runnable { public static void main(String[] args) { ThreadGroupDemo tg = new ThreadGroupDemo() tg.func() } public void func() { try { // create a parent ThreadGroup ThreadGroup pGroup = new ThreadGroup("Parent ThreadGroup") // create a child ThreadGroup for parent ThreadGroup ThreadGroup cGroup = new ThreadGroup(pGroup, "Child ThreadGroup") // returns the maximum priority of parent thread group int i = pGroup.getMaxPriority() System.out.println("Maximum priority of ParentThreadGroup =" + i) // create a thread Thread t1 = new Thread(pGroup, this) System.out.println("Starting " + t1.getName() + "...") t1.start() // create another thread Thread t2 = new Thread(cGroup, this) System.out.println("Starting " + t2.getName() + "...") t2.start() // block until the other threads finish t1.join() t2.join() } catch (InterruptedException e) { System.out.println(e.toString()) } } // implements run() public void run() { for(int i = 0i < 1000i++) { i++ } System.out.println(Thread.currentThread().getName() + " finished executing.") } }
让我们来编译和运行上面的程序，这将产生以下结果：
Maximum priority of ParentThreadGroup =10 Starting Thread-0... Starting Thread-1... Thread-0 finished executing Active threads in "Parent ThreadGroup" = 1 Thread-1 finished executing